SOLUTION: I need help with 3x^2 - 2x + 1 = 0 I came out with x = 2/6 + sqrt 8/6 Did I do this right?

Algebra.Com
Question 42170: I need help with 3x^2 - 2x + 1 = 0
I came out with x = 2/6 + sqrt 8/6
Did I do this right?

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
From 3x^2 - 2x + 1 = 0, we use the quadratic and get
x = (2 ± sqrt(4 - 12)) / 6
x = (2 ± sqrt(-8)) / 6
x = (2 ± 2i*sqrt(2)) / 6
x = (1 ± i*sqrt(2)) / 3

RELATED QUESTIONS

I need help with 3x^2 - 2x + 1 = 0 I came out with x = 2/6 + sqrt 8/6 Did I do this (answered by fractalier)
I dont remember what the rules are for reducing a linear equation with this many... (answered by elima)
The problem says for me to solve but I don't even know how to begin. I know I need an LCM (answered by stanbon)
I need help figuring out what to do with this 1/2 + 6/x =... (answered by allyw269)
I need to solve this radical equation using the power principle. Problem:... (answered by ankor@dixie-net.com)
I have an unsimplified equation and need to simplify it then solve for x: {{{(... (answered by josgarithmetic,Alan3354)
Here's what i did: the equation is 2-y=x-6. I'm trying to get it into standard form of a (answered by uma)
I need help solving this equation: 2x-3-(3x-1)=6 I tried solving for it and this is what (answered by jim_thompson5910)
Solve the equation. Sqrt(x^2 - 24) = Sqrt(x + 6) I am lost on this one. I came up... (answered by jsmallt9)