Solved by pluggable solver: Min/Max of a Quadratic Function |
The min/max of a quadratic equation is always at a point where its first differential is zero. This means that in our case, the value of => This point is a minima if value of coefficient of x2 is positive and vice versa. For our function the point x=0.5 is a Alternate method In this method, we will use the perfect square method. Step one: Make the coefficient of Maxima / Minima is decided from the sign of 'a'. If 'a' is positive then we have Minima and for 'a'negative we have Maxima. Step two: Now make the perfect square with the same Maxima / Minima lies at the point where this squared term is equal to zero. Hence, => This point is a minima if value of coefficient of x2 is positive and vice versa. For our function the point x=0.5 is a For more on this topic, refer to Min/Max of a Quadratic equation. |