SOLUTION: I need help solving this quadratic equation and leaving it in radical form I don't know how to set it to zero? I know how to use the quadratic formula so I need help on how to set

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Question 420301: I need help solving this quadratic equation and leaving it in radical form I don't know how to set it to zero? I know how to use the quadratic formula so I need help on how to set the equation to zero so I can solve using the quadratic formula? (x+8)(x-4)=-3(2x+5) thank you for your help
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
(x+8)(x-4)=-3(2x+5)
x^2-4x+8x-32=-6x-15
x^2+4x-32+6x+15=0
x^2+10x-17=0
Find the roots of the equation by quadratic formula
a= 1 , b =10 , c =-17 .
b^2-4ac=168



x1=1.48
...

x2=-11.48

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