SOLUTION: solve using the quadratic formula and leave the answer in radical form? Could you show work as I am very confused. Thanks. Karyn y^2+6y-1=0

Question 419764: solve using the quadratic formula and leave the answer in radical form? Could you show work as I am very confused. Thanks.
Karyn
y^2+6y-1=0
Found 2 solutions by Alan3354, Theo:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve using the quadratic formula and leave the answer in radical form? Could you show work as I am very confused. Thanks.
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=40 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.16227766016838, -6.16227766016838. Here's your graph:

Sub x for y
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x = -3 � sqrt(10)

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
equation is:

y^2 + 6y - 1 = 0

standard form of a quadratic equation is:

ax^2 + bx + c = 0

a is the coefficient of the x^2 term.
b is the coefficient of the x term.
c is the constant.

in your equation you have:

a = 1
b = 6
c = -1

the quadratic formula is:

you replace the a's and the b's and the c's with their respective values to get:

the * is the multiplication symbol.

in the formula you see it looks like a little square.

I typed a *. The formula generator program converted it to a little square.

you would simplify this expression to be shown as follows:

it can also be simplified further to be shown as:

it can even be simplified further to be shown as:

is the same thing as because equals which equals which equals .

since they only told you to leave the answer in radical form, then i suspect you're ok with any of the answers that still have a radical in them.

that's between you and your teacher as to how he/she wants to see the answer.

a graph of your equation looks like this:

you can see that the graph crosses the x-axis somewhere around x = -6.16 and x = .16 which is where the equation of indicates.

note that sqrt(10) is somewhere around 3.16...

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