Hi Using the vertex form of a parabola, where(h,k) is the vertex y=2x^2-6x-14 |completing the square to put into the vertex form y= 2(x-3/2)^2 -9/2 -14 y= 2(x-3/2)^2 -37/2 |vertex Pt(3/2,-37/2) x = 3/2 the line of symmetry CHECKING our Answer***