SOLUTION: The length of a rectangle is 7 feet less than twice the width. The perimeter is 64 feet. Find the length and width. L= ? feet w= ? feet

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Question 415878: The length of a rectangle is 7 feet less than twice the width. The perimeter is 64 feet. Find the length and width.
L= ? feet
w= ? feet

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Let x and (2x-7ft) represent the widthe and length respectively
Question states***
2(2x-7) + 2x = 64ft
Solving for x
6x = 78
x = 13ft, the width. The length is 19ft (26ft-7ft
CHECKING our Answer***
2*19ft + 2*13ft = 38ft + 26ft = 64ft


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