SOLUTION: I am having trouble with a quadratic word problem. The word problem is as follows: The sides of one square have length 3 m more than the sides of a second square. If the area of

Question 414895: I am having trouble with a quadratic word problem. The word problem is as follows:
The sides of one square have length 3 m more than the sides of a second square. If the area of the larger square is subtracted from 4 times the area of the smaller square, the result is 36 m^2. What are the lengths of the sides of each square?
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The sides of one square have length 3 m more than the sides of a second square. If the area of the larger square is subtracted from 4 times the area of the smaller square, the result is 36 m^2. What are the lengths of the sides of each square?
----
1st Square DATA:
Side = x
Area = x^2
---
2nd Square DATA:
side = x+3
Area = (x+3)^2
------
Equation:
4*smaller area - larger area = 36 m^2
4x^2 - (x+3)^2 = 36
---
4x^2-[x^2+6x+9] - 36 = 0
---
4x^-x^2-6x-9-36 = 0
3x^2-6x-45 = 0
-----
x^2-2x-15 = 0
(x-7)(x+2) = 0
Positive solution:
x = 7m (side of smaller square)
x+3 = 10m (side of larger square)
=====================================
Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the side of the larger square = m
The side of the smaller square = m
given:
m2

(can't use the negative root)

and

The sides are 5 m and 8 m
check answer:

OK
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