SOLUTION: please help me find the roots, lines of symmetry, and vertex for y=-x2+5x-4

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Question 414468: please help me find the roots, lines of symmetry, and vertex for y=-x2+5x-4
Found 3 solutions by stanbon, rfer, MathLover1:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
please help me find the roots, lines of symmetry, and vertex for
y=-x^2+5x-4
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-x^2+5x+? = y+4+?
----
Complete the square on the x-terms:
-(x^2-5+(5/2)^2) = y+4-(5/2)^2
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Factor:
-(x-(5/2))^2 = y + 16/4 - (25/4)
----
-(x-(5/2))^2 = y -9/4
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Symmetry line : x = 5/2
Vertex: (5/2 , (9/4))
----
Roots of y = -x^2+5x-4
Solve -x^2+5x-4 = 0
x^2-5x+4 = 0
(x-4)(x-1) = 0
x = 1 or x = 4
---
Cheers,
Stan H.

Answer by rfer(16322)   (Show Source): You can put this solution on YOUR website!
zero's =(1,0), (4,0)
vertex=(2.5,2.5)
axis=2.5

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
....factor





This is a quadratic equation (degree of 2), so
First, find x-intercepts,
Let and solve for :

........->.... and
........->....
So, the (roots) are (4,0) and (1,0)

Now, find the , let and solve for ,
, so the is (0,-4)

The axis of is just the average of the two ,

So, the axis of symmetry is
Since the sign of is negative then this function will have a maximum.
Now, to find it's maximum (vertex).
Formula for maximum value is
, , ( Coefficients of )

this is exactly , which is not surprising because the on the axis of .
Now, find the value corresponding to the value,
Substitute, into the equation and solve for ,




Summarize:
You should have more than enough now for a graph,
: (4,0) and (1,0)
: (0,-4)
maximum value (vertex) : (2.5,2.25)
axis of :




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