Hi

Solving for t

(2t-3)^2 + 13t = 14

4t^2 - 12t + 9 + 13t = 14

 4t^2 + t -5 = 0

factoring

(4t + 5)(t-1)= 0 Note: SUM of the inner product(5t) and the outer product(-4t) = t

(4t + 5)=0

    t = -5/4

(t-1)= 0

    t = 1 

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