Hi
Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin
Using the vertex form of a parabola,where(h,k) is the vertex
y = -3x^2-6x+5 |Completing the square
y = -3(x+1)^2 + 8 |Vertex is Pt(-1,8)& a Maximum as Parbola opens downward (a< 0)
0 = -3(x+1)^2 + 8 8/3 = (x+1)^2 x = -1 ± 2sqrt(2/3) {.633, -2.633}