Hi
Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin
Using the vertex form of a parabola,where(h,k) is the vertex
y = x^2-2x-3 |Completing the square
y = (x-1)^2 -4 |Vertex is Pt(1,-4)& a Minimum as Parbola opens upward (a> 0) x=1, the line of symmetry
0 = (x-1)^2 -4 4 = (x-1)^2 x = 1 ± 2 {-1,3}