Hi
Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin
Using the vertex form of a parabola,where(h,k) is the vertex
y = (-1/4)x^2+2x |Completing the square
y = -.25(x-4)^2 +4 |Vertex is Pt(4,4)& a Maximum as Parbola opens downward (a< 0) x = 4, the line of symmetry
0 = -.25(x-4)^2 +4 x = 4 ħsqrt(16) x = 4 ħ4 {0,8}