SOLUTION: A ball is thrown vertically with an initial velocity of 48ft per second. Its height above the ground after t seconds is given by h(t)=48t-16t squared. What is the maximum height in

Question 41289: A ball is thrown vertically with an initial velocity of 48ft per second. Its height above the ground after t seconds is given by h(t)=48t-16t squared. What is the maximum height in feet reaced by the ball. What is the height after 1 second, 2 seconds. How much time does it take for it to reach its maximum height. How much time does it take for it to hit the ground.
Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!
See my solution to this problem. http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.41288.html
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