SOLUTION: Hi Stuck with this, please help Find the area under y = cos 2t from t = 0 to t = 0.5. Thanks Tim

SOLUTION: Hi Stuck with this, please help Find the area under y = cos 2t from t = 0 to t = 0.5. Thanks Tim

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Question 412090: Hi Stuck with this, please help
Find the area under y = cos 2t from t = 0 to t = 0.5.

Thanks Tim
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the area under y = cos 2t from t = 0 to t = 0.5
-----------------
Integral = sin(2t)/2 + C
sin(1)/2 - sin(0)/2 = 0.8414/2 - 0
= 0.4207 sq units

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