Hi

Using the vertex form of a parabola,  where(h,k) is the vertex

 y = 1/4(x+2)^2+6   |Vertex is Pt(-2,6), Axis of symmetry is x = -2



 y = 2(x+2)(x+4)

 y = 2(x^2 + 6x + 8)

 y = 2[(x+3)^2 - 9 + 8]

 y = 2(x+3)^2 - 2   |Vertex is Pt(-3,-2), Axis of symmetry is x = -3



 

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