SOLUTION: Find an equation of the parabola that has a focus at (9,15) and a vertex at (9,8) in terms of y.

Question 409132: Find an equation of the parabola that has a focus at (9,15) and a vertex at (9,8) in terms of y.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
a focus at (9,15) and
a vertex at (9,8)

Since the of the and are the , they are one of top of the other, so this is a vertical parabola, where the part is squared.
Since the vertex is the focus, this is a parabola and is positive.
Since the vertex and focus are 15 �8 = 7 units apart, then .
And that's all I need for my equation, since they already gave me the vertex.

(x�h)^2=4p(y �k)
(x�9)^2 = 4*7(y �8)
(x�9)^2 = 28(y �8)
(x�9)^2/28= y�8

(x�9)^2/28 +8= y

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