SOLUTION: 4x^2=27x+7

Question 400635: 4x^2=27x+7
Answer by sofiyac(983) (Show Source): You can put this solution on YOUR website!
move everything to the left side, so subtract 27x from each side and subtract 7 from each side.

now we factor
now set each part equal to zero and solve for x
4x+1=0
4x=-1
x=-1/4
x-7=0
x=7

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