Hi

Using the vertex form of a parabola,  where(h,k) is the vertex

f(x) = -x^2 + 6x + 1    |completing the square

f(x) = -[(x-3)^2 - 9] + 1 

f(x) = -(x-3)^2 +10  vertex is Pt(3,10) Line of symmetry  x= 3





 

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