Hi

two positive numbers such that one is 6 less than twice the other

Let x and (2x-6) represent the numbers

Question states***

 (2x-6)^2 - x^2 = 1311

solving for x

4x^2 - 24x + 36 - x^2 = 1311

 3x^2 - 24x + 36 = 1311

 3x^2 -24x - 1275 = 0

  x^2 - 8x - 425   



  x = (8 ± 42)/2

 x = -17 and x = 25  Tossing out negative solution 

   x = 25, the other number is 44  (2*25-6)



CHECKING our Answer

 1936 - 625 = 1311 

RELATED QUESTIONS

The difference of two positive numbers is six. Their product is 223 less than the sum of... (answered by josgarithmetic,ikleyn,TeachMath)

Find two positive numbers such that the sum of the squares of the two numbers is 245 and... (answered by ikleyn,solver91311)

The difference between two positive numbers is 223 smaller than the sum of their squares.  (answered by richwmiller,ikleyn,greenestamps)

Are there two consecutive odd numbers such that the difference in their squares is... (answered by dabanfield)

One number is 6 less than the other. The sum of the squares of these two numbers is 20.... (answered by Fombitz)

The larger of two numbers is one less than twice the smaller number. The difference of... (answered by jojo14344)

Find two consecutive positive and odd integers such that the difference of their squares... (answered by Alan3354,Gersid)

find two consecutive positive odd integers such that the difference of their squares is... (answered by Alan3354)

One positive integer is 3 less than twice another. Find these two integers if the... (answered by oberobic)