Hi
f(x)= -5(x+3)^2 + 8 |adjusted for typo on the 'x'
Finding vertex
Using the vertex form of a parabola,where(h,k) is the vertex
f(x)= -5(x+3)^2 + 8 | Vertex is Pt(-3,8) Line of symmetry is x= -3
-5 = a < 0, parabola opens downward f(-3) = 8 is a maximum point for f(x)