SOLUTION: use the quadratic formula to solve the equation. If necessary, round answers to the nearest hundredth.
question 1 : 2a^2-46a+252=0
question 2 : x^2-4x=5
please answer thes
Algebra.Com
Question 395154: use the quadratic formula to solve the equation. If necessary, round answers to the nearest hundredth.
question 1 : 2a^2-46a+252=0
question 2 : x^2-4x=5
please answer these . thanks
Found 2 solutions by mananth, jsmallt9:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
question 1 : 2a^2-46a+252=0
/2
x^2-23x+121=0
x^2-14x-9x+121=0
x(x-14)-9(x-14)=0
(x-14)(x-9)=0
x=14, x=9
question 2 : x^2-4x=5
x^2-4x-5=0
x^2-5x+x-5=0
x(x-5)+1(x-5)=0
(x-5)(x+1)=0
x=5, x=-1
...
m.ananth@hotmail.ca
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
The solution provided by another tutor does not use the Quadratic Formula as the problem specifies and there is a typographics error in the first solution.
question 1 :
Dividing both sides by 2 will make the "a", "b" and "c" smaller. This will make the rest of the problem easier:
The Quadratic Formula:
which simplifies as follows:
In long form this is:
or
or
x = 14 or x = 9
question 2 :
One side needs to be zero so we start by subtracting 5 from each side:
The Quadratic Formula:
which simplifies as follows:
In long form this is:
or
or
x = 5 or x = -1
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