How do you compute the intercepts of a quadratic function? Intercepts are points where a graph crosses the x axis or the y axis. Every point on the x-axis has 0 for its y-coordinate. And vice-versa, that is, every point on the y-axis has 0 for its x-coordinate. A quadratic graph 1. Is either shaped like a U or an upside down U.or 2. Always has exactly 1 y-intercept 3. Sometimes has 2 x-intercepts, like the two graphed above 4. Sometimes has NO x-intercepts, like this one just below: 5. Sometimes has exactly ONE x-intercept, like this one below 6. Has as its general equation y = Ax² + Bx + C where A, B and C can represent positive or negative numbers, 7. B and/or C is sometimes 0, but A is never 0. How to find the y-intercept: Substitute 0 for x and solve for y: Then the y-intercept is (0, whatever you got) How to find the x-intercepts: Substitute 0 for y and solve for x: Then the x-intercept is (whatever you got, 0) Example 1: y = x² + 2x - 3 To find its y-intercept, substitute 0 for x, and solve for y y = 0² + 2(0) - 3 y = -3 So the y-intercept is the point (0, -3) To find its x-intercepts, substitute 0 for y, and solve for x 0 = x² + 2x - 3 x² + 2x - 3 = 0 (x + 3)(x - 1) = 0 x = -3, and x = 1 So the two x-intercepts are (-3, 0) and (1, 0) Its graph looks like this Example 2: f(x) = -x² + x - 1 Replace f(x) by y y = -x² + x - 1 To find its y-intercept, substitute 0 for x, and solve for y y = -0² + 0 - 1 y = -1 So the y-intercept is the point (0, 1) To find its x-intercepts, substitute 0 for y, and solve for x 0 = -x² + x - 1 x² - x + 1 = 0 That doesn't factor, so we use the quadratic equation and find _ x = 1/2 ± Ö3/2i which are imaginary, so there are no x-intercepts. Its graph looks like this Example 3: y = x² + 6x + 9 To find its y-intercept, substitute 0 for x, and solve for y y = 0² + 6(0) + 9 y = 9 So the y-intercept is the point (0, 9) To find its x-intercepts, substitute 0 for y, and solve for x 0 = x² + 6x + 9 x² + 6x + 9 = 0 (x + 3)(x + 3) = 0 x = -3, and x = -3 These are the same so there is only one x-intercept (-3, 0) Its graph looks like this It just "sits" on the x-axis at one point (-3, 0) Edwin