Hi

3x2 + 9x + 1 = 0



 

x is {-0.1156, -2.8844}

finding vertex by completing square

the vertex form of a parabola,  where(h,k) is the vertex

y = 3(x^2 + 3) + 1

y = 3[(x+3/2)^2 - 9/4] + 1

y = 3(x + 3/2)^2 -23/4  Vertex is Pt(-3/2,-23/4)





 

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