Hi
two consecutive integers
Let x and (x+1) represent the integers
Question States: Write as we Read
x(x+1) = 72 |Writing as we Read Sets Up this 'equation'
solving for x
x^2 + x = 72
x^2 + x -72 = 0
factoring
(x+9)(x -8)= 0 Note:SUM of the inner product(9x) and the outer product(-8x) = x
(x+9)= 0 x = -9 Consecutive Integers -9,-8
(x -8)= 0 x = 8 Consecutive Integers 8,9
both sets satisfy the conditions that x(x+1) = 72