Hi,  

Parabola with vertex at pt(-6,-1) and x-intercepts are (-9,0) and (-3,0)       

Using the vertex form of a parabola,  where(h,k) is the vertex

 y = a(x+6)^2 - 1 Using Pt(-3,0) to solve for a

 0 = a *3^2 - 1

 1 = 9a

 1/9 = a

y = 1/9(x+6)^2 - 1



 

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