SOLUTION: Find two consecutive even integers such that the sum of their squares is 52

Question 390358: Find two consecutive even integers such that the sum of their squares is 52
Found 2 solutions by user_dude2008, richard1234:
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
(2x)^2+(2x+2)^2=52
4x^2+4x^2+8x+4=52
4x^2+4x^2+8x+4-52=0
8x^2+8x-48=0
8(x^2+x-6)=0
8(x+3)(x-2)=0
x+3=0 or x-2=0
x=-3 or x=2

Numbers are: -6, -4 or 4, 6
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
This is kind of a guess and check problem since you know the integers are consecutive and even. It is easy to check that . Note that (-6, -4) also works.
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