SOLUTION: a man jumps off a cliff into water, given the function h(t) = -16t^2+16t+480 where t = time in seconds and h = height in feet At what height did the man jump? What was the the high

Question 389336: a man jumps off a cliff into water, given the function h(t) = -16t^2+16t+480 where t = time in seconds and h = height in feet At what height did the man jump? What was the the highest point he reached? and how many secs did he take to hit the water?

Found 2 solutions by richard1234, robertb:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
The man jumped at 480 feet (t=0, also if you know elementary physics you know that with constant acceleration, the position X is given as where x_0 is the original position)

The highest point he reached occurred at the vertex, which is at t = -b/2a = 1/2 second. Plugging in t = 1/2,

h(1/2) = -16(1/4) + 16(1/2) + 480 = 484 feet

To find the amount of time it took to hit the ground, we plug h(t) = 0 and solve:

I'll divide both sides by -16

(seconds)

Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
The man jumped off the cliff at 480 feet (The height of the cliff, when t = 0.)
The highest point reached is feet. (Or 4 feet above cliff level.)
To find the length of time it took him to hit the water, solve for t in
;
;
(t-6)(t+5) = 0
The man will hit the water after 6 seconds. (Eliminate the negative value of t.)
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