SOLUTION: how do i solve this quadratic function so i can then graph it? y=(x+3) (x-2)

Question 387077: how do i solve this quadratic function so i can then graph it? y=(x+3) (x-2)
Found 2 solutions by stanbon, tara0066:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do i solve this quadratic function so i can then graph it?
y=(x+3) (x-2)
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Plot a few points.
If x = 2, y = 0
If x = -3, y = 0
If x = 0, y = -6
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Plot those three points and draw a parabola opening upward
thru them to get:
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Cheers,
Stan H.
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Answer by tara0066(31) (Show Source): You can put this solution on YOUR website!
Well, this formula is the x-intercept formula (also known as roots). You can put each set equal to zero to solve for the x-intercepts.
x+3=0 Subtract your 3 over
x=-3
x-2=0 Add your 2 over
x=2
These are your roots, where your parabola is going to hit on the x-axis.
To get the vertex, you take the average of these two numbers. That will give you your x value for your vertex.
2+(-3)=-1/2 x=-1/2 You add the two values and divide by two.
y=(-1/2+3)(-1/2-2) Plug in the value for x and solve for y. This will give you the y value of vertex
y=(5/2)(-5/2)
y=-25/4 or -6 1/4
So vertex is at (-1/2, -6 1/4) This parabola is opening up because there is no negative out front of parenthesis, and it will cross the x-axis at 2 and -3. This should be enough information to graph this parabola.
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