SOLUTION: Given the quadratic function f(x)=x^2 - 6x + 9 find a value of x such that f(x)= 25

SOLUTION: Given the quadratic function f(x)=x^2 - 6x + 9 find a value of x such that f(x)= 25

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Question 384666: Given the quadratic function f(x)=x^2 - 6x + 9 find a value of x such that
f(x)= 25
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
We have
25 = x^2 - 6x + 9
Factoring, we obtain
25 = (x - 3)^2
One such value of x is 8 (the other one is -2).
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