SOLUTION: Originally, the dimensions of a rectangle were 18cm by 24cm. When both dimensions were decreased by the same amount, the area of the rectangle decreased by 117 sq. cm. Find the dim

Algebra.Com
Question 383851: Originally, the dimensions of a rectangle were 18cm by 24cm. When both dimensions were decreased by the same amount, the area of the rectangle decreased by 117 sq. cm. Find the dimensions of the new rectangle.
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
rectangle dimensions
18 by 24 cm
Area = 18*24=432 cm^2
..
let them be decreased by x
..
new dimensions =
18-x
24-x
..
area = (18-x)(24-x)
area = 432-18x-24x+x^2
area=432-42x+x^2
..
Original area - reduced rectangle area = 117
432-(432-42x+x^2)=117
432-432+42x-x^2=117
42x-x^2=117
x^2-42x+117=0
x^2-39x-3x+117=0
x(x-39)-3(x-39)=0
(x-3)(x-39)=0
So x= 3. x= 39 is not practical.
dimensions of new rectangle = 15cm by 21cm
..
m.ananth@hotmail.ca

RELATED QUESTIONS

Originally the dimensions of a rectangle were 20 cm by 23 cm. When both dimensions were... (answered by checkley77,stanbon)
Originally the dimensions of a rectangle were 12 cm by 7 cm. When both dimensions were... (answered by oberobic)
Originally the dimensions of a rectangle were 20 cm by 23 cm. When both dimensions were... (answered by drk,checkley77)
The original dimensions of a rectangle were 15cm by 20cm. When both dimensions were... (answered by nerdybill)
Originally the dimensions of a rectangle or 20 cm x 23 cm when the dimensions were... (answered by mananth)
The dimensions of a rectangle were originally 10 units by 12 units. The area of the... (answered by Boreal)
The original dimensions of a rectangle were 15cm by 20cm. When both dimensions were... (answered by anantha)
After reducing by an equal amount the length and width of a rectangle which were... (answered by greenestamps)
I need your help on the following word problem: A rectangle is 15cm wide and 18cm long.... (answered by gonzo,solver91311)