Hi,

graphing 

-x^2+12x=36

 x^2 -12x +36 = 0  

 factoring

 (x-6)(x-6) = 0 Note:SUM of the inner product(-6x) and the outer product(-6x) = -12x

 (x-6)= 0

 (x-6) = 0

x = 6  Pt(6,0) the x intercept

 x^2 -12x +36 = (x-6)^2  

the vertex form of a parabola,  where(h,k) is the vertex

here, the vertex is at Pt(6,0) a = 1 (a is positive, graph opens upward)



 

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