SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper. f(x)=x^2-8x-1

SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper. f(x)=x^2-8x-1

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Question 379460: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper.
f(x)=x^2-8x-1
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
The vertex of the quadratic is -b/2a = 4. Therefore the line of symmetry is x=4. Since the polynomial has a positive x^2 coefficient, the graph points upward, therefore x=4 must result in an absolute minimum. This value is just f(4) = -17.
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