SOLUTION: 23645=a(2)^2+b(2)+c
32015=a(20)^2+b(20)+c
33715=a(40)^2+b(40)+c
When I tried to put this in quadratic form I got
H=10t^2+245t+23115
From here I got stuck and couldn't figure
Algebra.Com
Question 379097: 23645=a(2)^2+b(2)+c
32015=a(20)^2+b(20)+c
33715=a(40)^2+b(40)+c
When I tried to put this in quadratic form I got
H=10t^2+245t+23115
From here I got stuck and couldn't figure out where to go. The assignment says to solve the quadratic formula.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
I'm not sure what you did.
Your solution is off.
.
.
[A]=
[x]=
[b]=
.
.
.
[A][x]=[b]
.
.
.
Using matrix inversion,
.
.
.
.
Then using the quadratic formula,
.
.
.
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