SOLUTION: what are the x-intercepts (to the nearest tenth) of the equation f(x)=-2x^2+4x+3

Algebra.Com
Question 378185: what are the x-intercepts (to the nearest tenth) of the equation f(x)=-2x^2+4x+3
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
x-intercepts (to the nearest tenth) of the equation f(x)=-2x^2+4x+3
0 = -2x^2 + 4x + 3





x = 1 - 1.58 = -.58 = -.6
x = 1 + 1.58 = 2.58 = 2.6
x- Intercepts: Pt(-.6,0) and Pt(2.6,0)

RELATED QUESTIONS

What are the x intercepts and y intercepts of... (answered by Fombitz)
what are the x-intercepts of the equation y=2x^2+4x-3 please answer with square roots... (answered by rapaljer)
what are the y intercepts of... (answered by MathLover1)
approximate the greatest real root of f(x) = x^3 - 2x -5 to the nearest... (answered by Alan3354)
approximate to the nearest tenth the negative real zeros of f(x)= x^3 - 2x^2 +... (answered by Fombitz)
Solve 4x+x(x-2)=0 / The solution(s) is/are x=? Find the x-intercepts of... (answered by lynnlo)
what are the x-intercepts of f(x)=|2x|- 6... (answered by Fombitz)
What are the x– and y–intercepts of the quadratic equation y = x^2 + 2x –... (answered by htmentor)
a-solve 4x^2-8 b-find the x intercepts of f(X)=4x^2-8 a- what are the solutions... (answered by jorel1380)