SOLUTION: solve(3x)^2-12√(3x)+27=0 using the quadratic equation.
explain the steps please?
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Question 378141: solve(3x)^2-12√(3x)+27=0 using the quadratic equation.
explain the steps please?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve(3x)^2-12√(3x)+27=0 using the quadratic equation.
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It is not a quadratic the way you have posted it.
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The following would be the quadratic form:
(3x)^2 - 12(3x) + 27 = 0
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Letting w = 3x you get:
w^2 - 12w + 27 = 0
(w-9)(w-3) = 0
w = 9 or w = 3
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Solving for "x":
3x=9 or 3x=3
x = 3 or x = 1
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Cheers,
Stan H.
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