SOLUTION: Hello. Confuse a bit with this, Find and classify the stationary points of the curve y = x^5 - x^3 and hence sketch the curve between the points x = -1 and x = 1. I G

Question 377702: Hello.
Confuse a bit with this,
Find and classify the stationary points of the curve y = x^5 - x^3 and hence sketch the curve between the
points x = -1 and x = 1.
I Got so far
Local minimum when x-0.775 and y = -0.186
Thanks in advance
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
To find the stationary points you have to get the derivative of y and then equate to zero. Then y' = = = 0. Then x = -0.775, 0, 0.775. At x = -0.775 there is a local max; at x = 0.775 there is a local min; at x = o there is an inflection point (neither a local max nor a local min; concavity changes from + to -).
RELATED QUESTIONS
f(x)= x^3-3x^2-9x+5 find and classify all stationary points. sketch the graph of... (answered by robertb)

Please help me solve this Consider the function f(x) = x^3 + px + q. (a) Determine the... (answered by rothauserc)

Please help me solve this Consider the function f(x) = x3 + px + q. (a) Determine the... (answered by Boreal)

Locate and classify the stationary points for: a. y(x)=4x^3-12x^2+4 (answered by Boreal)

Find the coordinates of the stationary points of the curve y = x^3(x−4) and... (answered by Fombitz)

Find and classify the stationary points of the function y(x) = sin x + cos x on the... (answered by Fombitz)

Consider the function f(x) = xe^x . (a) State the domain of f. (b) Find the vertical... (answered by Boreal)

a curve (dy/dx) = x^1/2-x^-1/2 the curve passes through point (4,2/3) �find the... (answered by Fombitz)

Please help me solve this problem: Use the function f(x)=sin(x)+cos(x), where... (answered by ikleyn)