Hi,

y^2-5y+6=0

Factoring

(y-3)(y-2) = 0 Note inner product(-3y) and outer product (-2y) have a sum of -5y

(y-3)=0

y = 3

(y-2) = 0 

y = 2 

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 how do i find the completion of squares for the equation 

y^2-5y+6=0

----

y^2-5y+? = -6+?

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Complete the square:

y^2-5y+(5/2)^2 = -6+(5/2)^2

---

Factor the left side:

(y-(5/2))^2 = (-24/4)+(25/4)

------

(y-(5/2))^2 = = 1/4

---

y-(5/2) = 1/2 or y-(5/2) = -1/2

----

y = 3 or y = 2

===============================

Cheers,

Stan H.

 

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