SOLUTION: What is the vertex of f(x)=x^2-4, and how did you figure it out? Thank you so much for your help!

SOLUTION: What is the vertex of f(x)=x^2-4, and how did you figure it out? Thank you so much for your help!

Algebra.Com

Question 365523: What is the vertex of f(x)=x^2-4, and how did you figure it out?
Thank you so much for your help!
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the general vertex form of the equation is ___ f(x) = a(x - h)^2 + k

"a" is the coefficient of the second order (squared) term , and (h,k) is the vertex

fitting your equation to the general form ___ f(x) = 1(x - 0)^2 + (-4)
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