SOLUTION: If a pro basketball player has a vertical leap of 20in, what is his hang time V=48t^2. Please help

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Question 363073: If a pro basketball player has a vertical leap of 20in, what is his hang time V=48t^2. Please help
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
V=48t^2 where V is the length of the vertical leap and t is the hang time
Assuming, the units are in inches for length and seconds for hang time
20in = 48t^2
20in/48 = t^2
.645 sec = t
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