SOLUTION: I am having a problem grasping the factoring of quadratic equations. I have an example 3x^2+18x+25=0 Now from what I understand I am suppose to find two numbers that add up to 25

Question 362029: I am having a problem grasping the factoring of quadratic equations. I have an example 3x^2+18x+25=0 Now from what I understand I am suppose to find two numbers that add up to 25 that also make 18 or so I thought. I am confused is there anyways to simplify this for me. I understand once I figure out this how to plug in the numbers for the x=-b sqrt of b^-4ac over 2a to get my answers
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
That's not factorable using integers.
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=24 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -2.18350341907227, -3.81649658092773. Here's your graph:

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