SOLUTION: Hi, I need as much help as I could possibly get in understanding how to solve quadratic equations Section 11.3. I am required to show all of the steps in detail of how I got the an

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Question 360729: Hi, I need as much help as I could possibly get in understanding how to solve quadratic equations Section 11.3. I am required to show all of the steps in detail of how I got the answer. Could someone please assist me with this problem:
Directions state:
Use the quadratic formula to solve equation.
1.)
x^2 + 15x+56=0

Found 2 solutions by jim_thompson5910, ewatrrr:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
For more help with the Quadratic Formula, check out this solver

Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=1, b=15, and c=56




Square 15 to get 225




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


or


Lets look at the first part:





Add the terms in the numerator

Divide


So one answer is






Now lets look at the second part:





Subtract the terms in the numerator

Divide


So another answer is




So our solutions are:

or


Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi,

*Note: format of a line for using the quadratic equaton 

ax^2 + bx + c = 0

x^2 + 15x + 56=0 (given in the necessary format, no preliminary steps need to be taken)

a = 1 b = 15 and c = 56

Using the quadratic formula to solve the equation.

 









x = -16/2 = -8

x = -14/2 = -7 

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