SOLUTION: f(x)=x^2-x-2/x^2-16 Looking to find the x-int

Question 360232: f(x)=x^2-x-2/x^2-16 Looking to find the x-int
Answer by neatmath(302) (Show Source): You can put this solution on YOUR website!
If this is the problem:

then proceed as such:

If you need to find the x-intercept(s), you are looking for the point where y=0

When y=0, you know that the point will definitely be on the x-axis, and you will end up with a point (x,0)

So, we just need to find the point where the function equals 0!

We know that the denominator can NEVER equal 0, so we can just remove the denominator, and set the numerator equal to 0. So,

Then we just need to factor this remaining polynomial if possible.

So since we know the 2 factors when multiplied equal 0, we know that either the first factor must equal 0, or the 2nd factor must equal 0.

So we have

or

or

Therefore the x-intercepts are 2 and -1 or

the x-intercepts are the points (2,0) and (-1,0)

I hope this helps!

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