SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
{{{ f(x) = 1/5(x+8)^2+2 }}}
1) The vertex is ???
2) The line of symm
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Question 358712: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
1) The vertex is ???
2) The line of symmetry is x= ??
3) What is the maximum/minimum value of f(x)
4) Is the value f (-8)=2, a minimum or maximum??
Could someone please help me and please show me what the graph looks like
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The way you rendered your function, the questions asked don't make any sense. Hence, I'm going to presume that you really meant:
\ =\ \frac{1}{5}\left(x\ +\ 8\right)^2\ +\ 2)
instead of what you actually wrote which was:
\ =\ \frac{1}{5\left(x\ +\ 8\right)^2}\ +\ 2)
Your function is in vertex form, \ =\ a\left(x\ -\ h\right)^2\ +\ k)
, which has a vertex at )
, an axis of symmetry at 
, a minimum or maximum value equal to the function value at the vertex, and the vertex is a maximum when 
or a minimum when 
Hint: Re-write your function thusly:
\ =\ \frac{1}{5}\left(x\ -\ (-8)\right)^2\ +\ 2)
John
My calculator said it, I believe it, that settles it
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