SOLUTION: What is Quadratic inform method how do you solve this: (x^2+2x)^2-5(x^2+2x)+6=0 and x^1/2-11x^1/4+30 How do you this Solve Equation 6x^3/5-24=0

Question 3581: What is Quadratic inform method
how do you solve this:
(x^2+2x)^2-5(x^2+2x)+6=0
and
x^1/2-11x^1/4+30

How do you this Solve Equation
6x^3/5-24=0
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
no idea what the "quadratic inform" method is, but you solve these as follows:

Given , this has a quadratic form, which you can see better if you let y=, because we can re-write the equation now as . This is now better to see and we can solve it by factorising:
(y-6)(y+1) = 0
so, y-6 = 0 OR y+1 = 0

so y=6 or y=-1

Hence or or, rewritten:

or

Now, solve these 2 equations to give the values of x. The first one looks to be a "formula" job, but the second can be factorised. You do these.

Second example...Let y = ...we then get . This can be factorised and hence solved quickly. Then go back and find the values of x.

Third... becomes then

now means either or . I shall use the first of these:

so x = cube root of 1024 (roughly 10.079).

jon.

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