SOLUTION: Question 35679:
A ball is thrown into the air with the velocity of 48 feet per second.
With h for height and t for time and height determined with h=16tsquared+48t+4.
How ma
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Question 35688: Question 35679:
A ball is thrown into the air with the velocity of 48 feet per second.
With h for height and t for time and height determined with h=16tsquared+48t+4.
How may seconds will the ball reach maximum height.
What is the maximum height.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
I am assuming that you mean . You can do this either algebraically or graphically. To do it algebraically, you need to realize that the graph is a paraola that opens down. The vertex of the parabola always occurs at .
In this problem a=-16, b=48, and c= 4, the vertex occurs at seconds.
To find the maximum height, substitute x=1.5 into the formula
(Got a calculator???
feet
Graphically, it is even easier. Just draw the graph , and find the vertex by calculator methods. The x coordinate of the vertex is the time it takes to get there, and the y coordinate of the vertex is the highest point.
R^2 at SCC
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