SOLUTION: A ball is thrown into the air with the velocity of 48 feet per second.
With h for height and t for time and height determined with h=16tsquared+48t=4.
How may seconds will the
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Question 35679: A ball is thrown into the air with the velocity of 48 feet per second.
With h for height and t for time and height determined with h=16tsquared+48t=4.
How may seconds will the ball reach maximum height.
What is the maximum height.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Did you state this problem correctly? You have two equal signs in the formula for h. Please take another look at this.
R^2 at SCC
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