SOLUTION: Hi, I'm being asked to solve for x by completing the square: -2x^2 + 12x - 6 = 0 -2x^2 + 12x = 6 < I moved the 6 to the other side x^2

SOLUTION: Hi, I'm being asked to solve for x by completing the square: -2x^2 + 12x - 6 = 0 -2x^2 + 12x = 6 < I moved the 6 to the other side x^2 - 6x = -3 < I divide

Question 355495: Hi, I'm being asked to solve for x by completing the square:
-2x^2 + 12x - 6 = 0
-2x^2 + 12x = 6 < I moved the 6 to the other side
x^2 - 6x = -3 < I divided everything by -2 to get the x^2 by itself
x^2 - 6x + 9 = 6 < I took half of the coefficient 6 (6/2 = -3), squared
it (9), and added it to both sides of the equation
This is where I get stuck. I'm supposed to write the left side in squared form, but because there is a plus and minus, it wouldn't be just one factor squared. Would I write this as (x-3)(x+3)? If so, how would I take the square root of that?
Thanks for any guidance you can provide!
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
(x - 3)^2 = 6

x - 3 = � sqrt(6)

x = 3 � sqrt(6)
RELATED QUESTIONS
The problem: 2x^2 - 12x - 7 = 0 the directions are to solve by completing the square.... (answered by Edwin McCravy)

It says: Solve by completing the square equation: m^2-25/2x=5/2 the 25/2 is a... (answered by dabanfield)

:49 It says: Solve by completing the square equation: m^2-25/2m=5/2 the 25/2 is a... (answered by scott8148)

Solve by completing the square.. What value should you add to each side of the equation? (answered by TimothyLamb)

12/√(5x+6)=√(2x+5) Ok I know you square each side to come up with... (answered by Fombitz)

Solve by completing the square. 2x^2-12x-18=0 How do you do it.... (answered by Earlsdon,ptaylor)

Factor by completing the square. x^2-12x-805 i can't remember how to do... (answered by richwmiller)

How can I solve x^2-12x=-36 by factoring? So far This is the work I have accomplished:... (answered by josmiceli,oberobic)

Solve the following by completing the square 2x^2 - x - 6 =... (answered by Fombitz)