SOLUTION: I need to solve the equation by completing the square. The following is my work but I get the wrong answer. Please let me know where I went wrong.
x^2 - 6x +3 = 0
x^2 -6x = -3
Algebra.Com
Question 355000: I need to solve the equation by completing the square. The following is my work but I get the wrong answer. Please let me know where I went wrong.
x^2 - 6x +3 = 0
x^2 -6x = -3
x^2 -6x -3^2 = -3-3^2
x^2 - 6x = -12
(x-6)^2 = sqrt -12
x-6 = sqrt -12
x=6+sqrt -12 and x = 6 - sqrt-12
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First, let's complete the square for the expression
Start with the given expression.
Take half of the coefficient to get . In other words, .
Now square to get . In other words,
Now add and subtract . Make sure to place this after the "x" term. Notice how . So the expression is not changed.
Group the first three terms.
Factor to get .
Combine like terms.
So after completing the square, transforms to . So .
So is equivalent to .
Now let's solve
Start with the given equation.
Add to both sides.
Combine like terms.
Take the square root of both sides.
or Break up the "plus/minus" to form two equations.
or Add to both sides.
--------------------------------------
Answer:
So the solutions are or .
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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