SOLUTION: Need help fast...Please someone show me how to do this. Solve X in (x-2)(x+5)=0 also Solve Y in 16(y-3)^2=64 and Solve Y in y^2+2y-3=0 I am so confused... Thanks

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Question 35398: Need help fast...Please someone show me how to do this.
Solve X in (x-2)(x+5)=0
also
Solve Y in 16(y-3)^2=64
and
Solve Y in y^2+2y-3=0
I am so confused...
Thanks

Answer by lyra(94)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=2,x=-5.
  • Graphical form: Equation was fully solved.
  • Text form: (x-2)*(x+5)=0 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( (x-2)*(x+5)=0 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION


Look at .
Notes known roots (x-(2))

Look at .
Remove unneeded parentheses around factor highlight_red%28+1+%29
It becomes .

Look at .
Remove extraneous '1' from product highlight_red%28+1+%29
It becomes .

Look at .
Remove unneeded parentheses around terms highlight_red%28+x+%29,highlight_red%28+5+%29
It becomes .

Look at .
Solved linear equation highlight_red%28+x%2B5=0+%29 equivalent to x+5 =0
It becomes .
Result:
This is an equation! Solutions: x=2,x=-5.

Universal Simplifier and Solver


Done!

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


Sorry, this expression cannot be simplified.

Universal Simplifier and Solver


Done!

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=16 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1, -3. Here's your graph:


Hope this helps,
lyra

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