SOLUTION: x squared-8x-29=(this equal sign has 3 lines)(x+a)squared+b, where a and b are constants. find the value of a and the value of b
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Question 352786: x squared-8x-29=(this equal sign has 3 lines)(x+a)squared+b, where a and b are constants. find the value of a and the value of b
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
This is a "Complete the Square" problem.
Start by setting the LHS equal to zero.
Add the opposite of the constant term to both sides:
Divide the coefficient on the first degree term by 2, square the result, and then add that result to both sides. -8 divided by 2 is -4. -4 squared is 16. Add 16 to both sides:
The quadradic trinomial in the LHS is now a perfect square. Factor it:
Add the opposite of the constant term to both sides:
Since both the original LHS and this new LHS are equal to zero, they must be equivalent, hence:
But the original LHS was equivalent to
, hence:
Therefore:
John

My calculator said it, I believe it, that settles it
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